nexusraven

Nexus Raven 是一款为函数调用任务设计的 130 亿参数模型。

此模型已更新至 NexusRaven-V2，是经过更新的开源且商业可行的函数调用模型。

• 多功能函数调用能力：能够在许多具有挑战性的情况下生成单个函数调用、嵌套调用和并行调用。
• 完全可解释性：能够为生成的函数调用生成非常详细的解释。此行为可以关闭，以便在推理过程中节省令牌。
• 性能亮点：在涉及嵌套和复合函数的人工生成的用例中，函数调用成功率最高可比 GPT-4 高出 7%。
• 对未见数据的泛化：从未在评估中使用的函数上进行过训练。
• 商业许可：训练不涉及由 GPT-4 等专有 LLM 生成的任何数据。在商业应用程序中部署时，您对模型拥有完全控制权。

示例提示

Function:
def get_weather_data(coordinates):
    """
    Fetches weather data from the Open-Meteo API for the given latitude and longitude.

    Args:
    coordinates (tuple): The latitude of the location.

    Returns:
    float: The current temperature in the coordinates you've asked for
    """

Function:
def get_coordinates_from_city(city_name):
    """
    Fetches the latitude and longitude of a given city name using the Maps.co Geocoding API.

    Args:
    city_name (str): The name of the city.

    Returns:
    tuple: The latitude and longitude of the city.
    """

User Query: {query}<human_end>

这将生成类似于

Call: get_weather_data(coordinates=get_coordinates_from_city(city_name='Seattle'))<bot_end>
Thought: The function call `get_weather_data(coordinates=get_coordinates_from_city(city_name='Seattle'))` answers the question "What's the weather like in Seattle right now?" by following these steps:

1. `get_coordinates_from_city(city_name='Seattle')`: This function call fetches the latitude and longitude of the city "Seattle" using the Maps.co Geocoding API.
2. `get_weather_data(coordinates=...)`: This function call fetches the current weather data for the coordinates returned by the previous function call.

Therefore, the function call `get_weather_data(coordinates=get_coordinates_from_city(city_name='Seattle'))` answers the question "What's the weather like in Seattle right now?" by first fetching the coordinates of the city "Seattle" and then fetching the current weather data for those coordinates.

参考资料

GitHub

Hugging Face